Trihybrid Cross Probability:
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Trihybrid cross probability calculates the chance of specific genotype combinations when three heterozygous traits are crossed (AaBbCc × AaBbCc). The total possible outcomes is 64 (4³).
The calculator uses the probability equation:
Where:
Explanation: For each heterozygous trait, there are 4 possible gametes (A or a, B or b, C or c). With three traits, there are 4 × 4 × 4 = 64 possible combinations.
Details: Understanding trihybrid crosses helps predict offspring genotype probabilities, which is fundamental in genetics research and breeding programs.
Tips: Enter the number of favorable outcomes (1-64). The calculator will compute the probability as a decimal and percentage.
Q1: Why 64 possible outcomes?
A: Each heterozygous gene pair (Aa) produces 2 gamete types. With three independent genes, it's 2 × 2 × 2 = 8 gamete types per parent, and 8 × 8 = 64 possible zygotes.
Q2: How to determine favorable outcomes?
A: Use Punnett squares or probability rules to count desired genotype combinations.
Q3: What's the probability of AABBCC offspring?
A: 1/64 (1.56%), as there's only one way to get this homozygous dominant combination.
Q4: What about AaBbCc offspring?
A: 8/64 (12.5%), as there are 8 possible gamete combinations that produce this heterozygous genotype.
Q5: Does this apply to linked genes?
A: No, this assumes genes are on different chromosomes or recombine independently.