molecalculator

Heat, Energy & Rates

Gibbs Free Energy Calculator and Formula

Calculator No. 08-0256 · Updated · Formula and assumptions shown below

Gibbs free-energy change ΔG -24.907 kJ/mol
Absolute temperature
298.15 K
= Temperature + 273.15
Enthalpy change ΔH
-10 kJ/mol
Set in the form below
Temperature
25 °C
Set in the form below
You enter
Enthalpy change ΔH (kJ/mol), Temperature (°C), Entropy change ΔS (J/(mol·K))
You get
Gibbs free-energy change ΔG (kJ/mol), Absolute temperature (K)
Rounding
3 dp · 2 dp

For study and lab planning. The result follows from the numbers you enter and the formula shown. Check it against your method before you weigh, mix or dilute anything, follow the safety data sheet and your supervisor, and do not use it for clinical, dosing or medication work.

This calculator finds the Gibbs free-energy change, ΔG, from enthalpy change, ΔH, temperature, and entropy change, ΔS. Enter ΔH in kJ/mol, temperature in °C, and ΔS in J/(mol·K); the result is ΔG in kJ/mol, with the temperature also shown in kelvin.

Formula

At constant temperature and pressure, the Gibbs free-energy change is calculated as:

ΔG = ΔH − TΔS

  • ΔG is the Gibbs free-energy change, in kJ/mol in this calculator.
  • ΔH is the enthalpy change, in kJ/mol.
  • T is absolute temperature, in kelvin: T = temperature in °C + 273.15.
  • ΔS is the entropy change, in J/(mol·K).

Because ΔH is entered in kJ/mol while ΔS is entered in J/(mol·K), the entropy term is converted to kJ/mol by dividing T × ΔS by 1000. In full, the calculator evaluates ΔG = ΔH − [(temperature in °C + 273.15) × ΔS / 1000]. Rounding is applied only to the displayed result.

Worked Example

Using the default inputs, ΔH = −10 kJ/mol, temperature = 25 °C, and ΔS = 50 J/(mol·K):

  1. Convert the temperature to kelvin: T = 25 + 273.15 = 298.15 K.
  2. Calculate the entropy contribution: TΔS = 298.15 × 50 = 14907.5 J/mol = 14.9075 kJ/mol.
  3. Subtract it from the enthalpy change: ΔG = −10 − 14.9075 = −24.9075 kJ/mol.

Rounded to three decimal places, the calculator returns −24.908 kJ/mol, and reports the temperature as 298.15 K to two decimal places.

Assumptions

  • The equation applies to a specified process at constant temperature and pressure.
  • ΔH and ΔS refer to the same reaction or process, in the same direction and on the same per-mole basis.
  • Temperature is converted from °C to K using the exact offset 273.15.
  • The entered changes are treated as applicable at the stated temperature. If they vary substantially with temperature, use temperature-dependent thermodynamic data instead of this simple calculation.

How to Interpret ΔG

A negative ΔG indicates that the process is thermodynamically favorable in the forward direction under the stated conditions; a positive ΔG indicates that the reverse direction is favorable. If ΔG is zero, the system is at equilibrium for that process under those conditions. “Favorable” does not mean fast: Gibbs free energy describes thermodynamic direction, not reaction rate. A reaction with negative ΔG can still proceed extremely slowly if it faces a substantial activation-energy barrier.

The sign is not a permanent label for a reaction. ΔG depends on temperature, pressure, and the composition of the system. The calculation from standard or specified ΔH and ΔS gives a useful estimate only when those values match the conditions and process being considered.

What the Equation Means

Enthalpy change, ΔH, captures heat released or absorbed at constant pressure. Entropy change, ΔS, describes how energy and matter are dispersed among the possible arrangements of a system and its surroundings. The term TΔS expresses the energetic importance of that entropy change at a particular temperature. Gibbs free energy combines these effects into one quantity useful for assessing spontaneity at constant temperature and pressure.

The signs of ΔH and ΔS help explain how temperature can change the outcome:

  • If ΔH is negative and ΔS is positive, both terms favor negative ΔG at all positive temperatures.
  • If ΔH is positive and ΔS is negative, both terms make ΔG positive at all positive temperatures.
  • If ΔH and ΔS are both negative, the process may be favorable at lower temperatures, where the enthalpy term can dominate.
  • If ΔH and ΔS are both positive, the process may be favorable at higher temperatures, when the TΔS contribution is large enough.

For a simple case with temperature-independent ΔH and ΔS, the temperature where ΔG changes sign can be estimated by setting ΔG = 0, giving T = ΔH/ΔS. The ratio must use consistent units; if ΔH is in kJ/mol and ΔS in J/(mol·K), convert ΔH to J/mol first. This estimate is not reliable across a broad temperature range when heat capacities or phase changes matter.

Standard and Actual Gibbs Energy

A frequent source of confusion is the difference between standard reaction Gibbs energy, ΔG°, and the Gibbs energy change under actual concentrations, ΔG. The calculator uses the inputs you provide; it does not automatically determine whether they are standard-state values. For a reaction at a specified temperature, the relationship is:

ΔG = ΔG° + RT ln Q

Here, R is the gas constant, 8.31446261815324 J/(mol·K), and Q is the dimensionless reaction quotient constructed from the activities of products and reactants. For ideal dilute solutions, activities are often approximated using concentrations relative to a standard concentration; gases may be approximated using partial pressures relative to a standard pressure. These approximations have limits, especially in concentrated or non-ideal systems.

At equilibrium, Q equals the equilibrium constant K and ΔG is zero, so ΔG° = −RT ln K. Thus, a negative ΔG° says the equilibrium favors products relative to the chosen standard states, but it does not by itself state the composition at every nonstandard condition.

Common Calculation Errors and Limits

  • Mixing units: Do not subtract J/mol directly from kJ/mol. This calculator divides TΔS by 1000 to convert joules to kilojoules.
  • Using Celsius in TΔS: Temperature in the equation must be kelvin. A Celsius value cannot be substituted directly.
  • Reversing signs: ΔH and ΔS must describe the same reaction direction. Reversing a reaction reverses the sign of both changes and of ΔG.
  • Confusing spontaneity with speed: ΔG does not predict how quickly equilibrium is reached.
  • Overinterpreting rounded data: A result close to zero may be uncertain if the input thermodynamic values are approximate. Keep extra digits during intermediate calculations and report only precision justified by the data.

The equation ΔG = ΔH − TΔS is a compact calculation, not a substitute for condition-specific thermodynamic data. For temperature-dependent properties, non-ideal mixtures, electrochemical systems, or reactions where composition changes significantly, use the appropriate thermodynamic model and data. For bench work, follow your lab method, the safety data sheet (SDS), and your supervisor.

Frequently Asked Questions

What does a negative Gibbs free-energy change mean?
It means the forward process is thermodynamically favorable at the stated conditions. It does not guarantee that the process is rapid or occurs without an activation barrier.

Why must temperature be in kelvin?
The TΔS term uses absolute temperature, whose zero is absolute zero. Convert Celsius by adding 273.15 before multiplying by entropy change.

Can Gibbs free energy be positive?
Yes. Positive ΔG means the forward direction is unfavorable under the specified conditions, while the reverse direction is favorable. Changing temperature or composition can change the value.

Is ΔG the same as ΔG°?
No. ΔG° refers to a defined standard state. Actual ΔG also depends on the system’s composition, as described by ΔG = ΔG° + RT ln Q.

Does negative ΔG mean a reaction happens instantly?
No. ΔG describes thermodynamic favorability, not reaction speed. Kinetics and activation energy determine how quickly a process proceeds.

Related

Formula used
in dh | Enthalpy change ΔH | kJ/mol | -10 | -
in t | Temperature | °C | 25 | -273.15
in ds | Entropy change ΔS | J/(mol·K) | 50 | -
out dg | Gibbs free-energy change ΔG | kJ/mol | dh - ((t + 273.15) * ds / 1000) | 3
out tk | Absolute temperature | K | t + 273.15 | 2

Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation with the constants and conversion factors written on the page, rounded as each result states. See method and constants, the disclaimer or report an error.

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