Nuclear Fusion Energy Calculation:
Where:
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The equation \( E = mc^2 \) represents the mass-energy equivalence principle from Einstein's theory of relativity. In nuclear reactions, small amounts of mass are converted to large amounts of energy.
The calculator uses Einstein's mass-energy equivalence formula:
Where:
For nuclear fusion of hydrogen to helium, the mass defect per reaction is approximately 0.0048 atomic mass units (7.97 × 10⁻³⁰ kg).
Details: When 2 hydrogen atoms fuse to form 1 helium atom, about 0.7% of the mass is converted to energy. This powers stars and could be a future clean energy source.
Tips: Enter the mass defect in kilograms (1 atomic mass unit = 1.660539 × 10⁻²⁷ kg). Optionally enter moles of reactions (1 mole = 6.022 × 10²³ reactions).
Q1: What's the mass defect for hydrogen fusion?
A: For 2H → He fusion, Δm ≈ 0.0048 u (7.97 × 10⁻³⁰ kg) per reaction, releasing ~4.3 × 10⁻¹² J.
Q2: How much energy per mole of fusion?
A: 1 mole of H→He reactions releases ~2.6 × 10¹² J (equivalent to ~600 tons of TNT).
Q3: Why is the energy release so large?
A: Because c² is an enormous number (9 × 10¹⁶ m²/s²), so tiny mass defects produce huge energy.
Q4: How does this relate to stars?
A: The Sun converts ~600 million tons of H to He each second, with 4 million tons becoming energy.
Q5: What's the efficiency of mass-energy conversion?
A: Nuclear fusion converts about 0.7% of mass to energy, compared to ~0.0000001% for chemical reactions.