molecalculator

Acids, Bases & Buffers

pKa Calculator From Kb: Convert Base Strength

Calculator No. 06-0254 · Updated · Formula and assumptions shown below

The calculator on this page is switched off while it is checked. The formula is below, and the worked example shows how to do the sum by hand.

For study and lab planning. The result follows from the numbers you enter and the formula shown. Check it against your method before you weigh, mix or dilute anything, follow the safety data sheet and your supervisor, and do not use it for clinical, dosing or medication work.

A pKa-from-Kb calculator converts a base dissociation constant, Kb, into the pKa of its conjugate acid. Enter Kb as a dimensionless value; the calculator returns pKa and the corresponding Ka, assuming both constants refer to a conjugate acid–base pair at the same temperature and under compatible conditions.

Formula

For a conjugate acid HA and its base A−, the constants are related by KaKb = Kw. Therefore, Ka = Kw / Kb, and pKa = −log10(Ka) = −log10(Kw / Kb).

  • Kb is the base dissociation constant of A−, dimensionless when expressed using activities relative to their standard states. For introductory calculations, tabulated concentration-based constants are often treated as dimensionless.
  • Kw is the ion product of water, dimensionless on the same convention. At 25 °C in dilute water it is approximately 1.0 × 10−14.
  • Ka is the acid dissociation constant of the conjugate acid HA.
  • pKa is −log10(Ka), a logarithmic measure of acid strength.

The first calculator result is pKa; the second is Ka. Kw is not exactly 1.0 × 10−14 at every temperature. Change its input when a reliable value for the relevant temperature and convention is available. The calculator requires positive Kb and Kw values because logarithms and this equilibrium relationship are not defined for zero or negative constants.

Worked Example

Using the defaults, Kb = 1.8 × 10−5 and Kw = 1.0 × 10−14:

  1. Find Ka: Ka = Kw / Kb = (1.0 × 10−14) / (1.8 × 10−5) = 5.5556 × 10−10.
  2. Take the negative base-10 logarithm: pKa = −log10(5.5556 × 10−10) = 9.2553.

The displayed results are pKa = 9.2553 and Ka = 5.55555556 × 10−10 (shown to eight decimal places by the calculator’s numeric output; a calculator may instead format very small values in scientific notation).

Assumptions

  • The input Kb belongs to the base whose conjugate acid’s pKa is wanted.
  • Ka, Kb, and Kw use compatible definitions and refer to the same temperature.
  • The standard dilute-water approximation is appropriate for interpreting the supplied constants; activity effects may matter in concentrated or high-ionic-strength solutions.
  • The default Kw, 1.0 × 10−14, is the familiar approximate value at 25 °C, not a universal constant for all temperatures.

How the Conversion Works

A base accepts a proton from water. For A−, the equilibrium can be written A− + H2O ⇌ HA + OH−. The conjugate acid dissociates in the reverse direction: HA + H2O ⇌ H3O+ + A−. Combining these equilibria gives the relationship KaKb = Kw.

Once Ka is calculated, pKa is simply its negative common logarithm. The logarithm means pKa does not change linearly with Ka: a tenfold decrease in Ka raises pKa by one unit. Similarly, for a fixed Kw, a tenfold increase in Kb raises the conjugate acid’s pKa by one unit.

Choosing and Checking Kb

Use a Kb value for the specific base and, where specified, temperature, solvent, and standard-state convention. A tabulated value may be reported as a concentration-based equilibrium constant or as a thermodynamic constant based on activities. Do not mix a constant from one convention with a Kw from another without checking that the comparison is valid.

  • Check the chemical identity and conjugate pair. The Kb must describe A− if the requested result is the pKa of HA.
  • Check whether the table gives Kb or pKb. They are not interchangeable: pKb = −log10(Kb).
  • Check the temperature. The default Kw is for approximately 25 °C; equilibrium constants can shift as temperature changes.
  • Keep the numerical value in scientific notation when it is small. For example, 1.8 × 10−5 is not 1.8 × 105.

If a source gives pKb rather than Kb, first convert it using Kb = 10−pKb, then enter that positive Kb value. Equivalently, when the same compatible Kw is used, pKa = pKw − pKb, where pKw = −log10(Kw). At 25 °C, the familiar approximation pKw ≈ 14 gives pKa ≈ 14 − pKb.

Interpreting Results and Common Errors

A higher pKa means the conjugate acid is weaker as an acid under the stated conditions; it does not mean the base itself is weaker. For a conjugate pair at 25 °C in dilute water, a stronger base has a weaker conjugate acid and therefore a higher pKa. Keep track of which member of the pair the question asks about.

A common shortcut is pKa = 14 − pKb. This is only an approximation tied to pKw ≈ 14, usually near 25 °C in water. The more general expression is pKa = pKw − pKb. Using 14 at a different temperature, or for a different solvent, can give a misleading result.

Another frequent error is taking the logarithm of Kb directly and reporting it as the conjugate acid’s pKa. The correct sequence is to calculate Ka = Kw/Kb, then take −log10(Ka). Also avoid rounding Ka too early: retaining several significant figures until the final logarithm helps prevent avoidable rounding drift. Report pKa precision in keeping with the reliability of the source constants.

Limits of the Calculation

This conversion relates equilibrium constants; it does not predict the pH of a particular solution. A pH calculation may also require concentration, temperature, charge balance, and a model for activities or other equilibria. For very dilute solutions, concentrated electrolytes, or unusual solvents, simple concentration-based textbook constants may not accurately describe measured behavior.

For polyprotic acids or bases, identify the specific step and conjugate pair. A molecule with multiple protonation states can have several Ka and Kb values, each belonging to a distinct equilibrium. Do not apply one base constant to every protonation step. In laboratory work, follow your lab method, the safety data sheet (SDS) and your supervisor.

Frequently Asked Questions

How do I calculate pKa from Kb?
Use pKa = −log10(Kw/Kb). At about 25 °C in water, if Kw is approximated as 1.0 × 10−14, this is approximately 14 − pKb, where pKb = −log10(Kb).

What is the relationship between pKa and pKb?
For a conjugate acid–base pair, pKa + pKb = pKw when the constants use compatible conventions and conditions. Near 25 °C in dilute water, pKw is approximately 14, so pKa + pKb is approximately 14.

Can I use pKb instead of Kb in the calculator?
No. This calculator’s input is Kb, not pKb. Convert first with Kb = 10−pKb, then enter the result. Alternatively, calculate pKa from pKw − pKb directly.

Why does temperature matter when converting Kb to pKa?
Kw changes with temperature, and acid and base equilibrium constants also depend on temperature. Use constants measured or tabulated for compatible conditions; the default Kw is only an approximate 25 °C value.

Does a higher pKa mean a stronger base?
Not by itself. pKa describes the conjugate acid. Within a comparable conjugate pair, a higher conjugate-acid pKa corresponds to a stronger base, but comparisons depend on solvent and conditions.

Related

Formula used
in kb | Base dissociation constant Kb | - | 1.8e-5 | 0
in kw | Water ion product Kw | - | 1e-14 | 0
out pka | Conjugate-acid pKa | - | -log10(kw / kb) | 4
out ka | Conjugate-acid dissociation constant Ka | - | kw / kb | 8

Each line is one input (in, sel, list) or one result (out: label, unit, formula, decimals). How the calculators work

Method: the standard formula for this calculation with the constants and conversion factors written on the page, rounded as each result states. See method and constants, the disclaimer or report an error.

More in this section

The whole Acids, Bases & Buffers section →